If it's not what You are looking for type in the equation solver your own equation and let us solve it.
25-132x+168x^2=0
a = 168; b = -132; c = +25;
Δ = b2-4ac
Δ = -1322-4·168·25
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-132)-4\sqrt{39}}{2*168}=\frac{132-4\sqrt{39}}{336} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-132)+4\sqrt{39}}{2*168}=\frac{132+4\sqrt{39}}{336} $
| 60+2x=3x+24 | | z/5-6=5/6 | | -6(2-4)+8w=2(w+9) | | 7x-7=-(2x-5) | | -2x+-10=-14+-2x+-18 | | 22-7x=7x+22 | | 4(-3s+2.7)=-9.8s+13= | | 4n=196 | | -12m-17=-53 | | 7v=336 | | 2x(9x-9)-63=4x(3x-42)+193 | | 7a=112 | | n-3=35 | | (x+14)/6=3 | | d+7=20 | | 34=2(y+5)-5y | | 5x+-5=12 | | 8x+5/8=9x+1/8 | | (x-45)/45=0.2 | | (x-45)/45=20 | | X+5/3-x=-15x/10 | | (3/5)^2x=27/125 | | 176-32x=0 | | (X+5)/3-x=(-15x)/10 | | -3/7=-5/8-x | | (X+5)/3)-x=(-15x)/10) | | c2=125 | | 3(r-4)=-4+3r | | -3(3x3x-5)=6x | | 2/6=n/23 | | d+4=26 | | 5q=70 |